A ray of light travelling in water is inciden | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When a light ray travels from a denser medium (water) to a rarer medium (air) and the angle of incidence $	heta$ is less than the critical angle,

Vedclass · Accepted Answer

a reflected ray and a refracted ray and the angle between them would be less than $180^o - 2	heta$

Vedclass · Answer

(C) When a light ray travels from a denser medium (water) to a rarer medium (air) and the angle of incidence $	heta$ is less than the critical angle,both reflection and refraction occur.According to the law of reflection,the angle of reflection is equal to the angle of incidence,which is $	heta$.According to Snell's law,the angle of refraction $r$ is greater than the angle of incidence $	heta$ because the light is moving from a denser to a rarer medium $(r > 	heta)$.The angle between the reflected ray and the surface is $90^o - 	heta$.The angle between the refracted ray and the surface is $90^o - r$.The angle between the reflected ray and the refracted ray is the sum of the angle between the reflected ray and the surface,the surface itself $(180^o)$,and the angle between the refracted ray and the surface is not the correct way to visualize it. Instead,consider the straight line representing the interface.The angle between the reflected ray and the refracted ray is $180^o - (	ext{angle of reflection} + 	ext{angle of refraction}) = 180^o - (	heta + r)$.Since $r > 	heta$,it follows that $	heta + r > 2	heta$.Therefore,$180^o - (	heta + r) Thus,the angle between them is less than $180^o - 2	heta$.

$A$ ray of light travelling in water is incident on its surface open to air. The angle of incidence is $\theta$,which is less than the critical angle. Then there will be

Similar Questions

Explain the use of optical fibre in the medical field.

Light travels in two media $A$ and $B$ with speeds $1.8 \times 10^8 \ m/s$ and $2.4 \times 10^8 \ m/s$ respectively. Then the critical angle between them is

For the given incident ray as shown in the figure,what is the minimum refractive index of the prism required for total internal reflection of this ray?

$A$ glass prism $(\mu = 1.5)$ is dipped in water $(_a\mu_w = 4/3)$ as shown in the figure. $A$ light ray is incident normally on the surface $AB$. It reaches the surface $BC$ after being totally internally reflected at the surface $AC$,if:

$A$ glass prism of refractive index $1.5$ is immersed in water (refractive index $\frac{4}{3}$) as shown in the figure. $A$ light beam incident normally on the face $AB$ is totally internally reflected at the face $AC$ to reach the face $BC$,if:

Vedclass Test Series

Exam Paper Generator

Online Exam Module